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Author Question: Starting with a primary alkyl bromide, which of the choices given results in an overall increase in ... (Read 70 times)

mmmmm

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Question 1

Select an appropriate synthetic route of the compound shown starting with 4-methyl-2-pentanol.



◦ 1. TsCl, pyr; 2. KOtBu; 3. HBr/ROOR; 4.

◦ 1. TsCl, pyr; 2. KOtBu; 3. HCl/ROOR; 4.

◦ 1. TsCl, pyr; 2. KOtBu; 3. HBr/ROOR; 4.

◦ 1. TsCl, pyr; 2. KOtBu; 3. HBr; 4. H3O+; 5.

◦ 1. TsCl, pyr; 2. KOtBu; 3. HBr/ROOR; 4.

Question 2

Starting with a primary alkyl bromide, which of the choices given results in an overall increase in the length of the carbon skeleton by one carbon?
◦ substitute bromide with acetylide, then cleave the triple bond
◦ substitute bromide with methoxide
◦ eliminate hydrogen bromide to produce an alkene
◦ substitute bromide with acetylide, then reduce the alkyne to an alkene


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Marked as best answer by mmmmm on Feb 17, 2022

hvhf4k+549qz8f218jyo@shar

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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mmmmm

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Reply 2 on: Feb 17, 2022
Gracias!


recede

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Reply 3 on: Yesterday
Great answer, keep it coming :)

 

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