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Author Question: Suppose the cumulative distribution function (CDF) of continuous random variableXis defined as ... (Read 109 times)

moore.cailinf

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on: Feb 26, 2023

Question 1

Suppose the cumulative distribution function (CDF) of continuous random variableX is defined as follows:

\(\style{font-family:Times New Roman;}{F(x)=\text{P}(X\leq x)=1-\frac1x}\)

where 1 ≤x < ∞. What is P(1.5 ≤X ≤ 2)?


◦

0.3333


◦

0.5000


◦

0.1667


◦

0.2500



Question 2

Suppose the cumulative distribution function (CDF) of continuous random variableX is defined as follows:

​

\(\style{font-family:Times New Roman;}{F(x)=\text{P}(X\leq x)=1-\frac1{2x+3}}\)

​

where 1 ≤x< ∞. What is P(X< 3)?


◦

0.8571


◦

0.8889


◦

0.1111


◦

0.1429

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Marked as best answer by moore.cailinf on Feb 26, 2023

ekattan2

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Reply #1 on: Feb 26, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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moore.cailinf

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Reply 2 on: Feb 26, 2023
:D TYSM

bblaney

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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