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Author Question: Which of the following statements correctly describes the treatment sum of squares in one-way ANOVA? (Read 74 times)

connormoss

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on: Feb 26, 2023
Which of the following statements correctly describes the treatment sum of squares in one-way ANOVA?

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It equals the number of columns (or rows) multiplied by the sum of the squared deviations of the row-block sample means from the grand mean.


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It equals the number of rows (or columns) multiplied by the sum of the squared deviations of the column-block sample means from the grand mean.


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It equals the sum of the square deviations between each block sample mean and the grand mean, multiplied by the number of observations made for each block, multiplied by the number of observations per cell.


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It equals the sum of the squared deviations between each treatment sample mean and the grand mean, multiplied by the number of observations made for each treatment.

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Marked as best answer by connormoss on Feb 26, 2023

3ginamay

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Reply #1 on: Feb 26, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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connormoss

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Reply 2 on: Feb 26, 2023
Wow, this really help

robbielu01

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Reply 3 on: Yesterday
:D TYSM

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