A small town claims that it needs rezoning to accommodate its current growth. The town wants to re-designate a current residential area as commercial. To gain approval from the zoning commission, it must show that the commercial taxes paid in this area are significantly higher, on average, than those paid in other residentially zoned areas. A random sample of 16 dwellings in standard residential areas (sample 1) yields an average commercial tax of $25,000 with a standard deviation of $11,000. A sample of 15 dwellings in the “rezoned” area (sample 2) has an average commercial tax of $55,800 with a standard deviation of $2500. Assume that the populations in question are both normal and have unequal variance. Construct a 90% confidence interval on the population mean difference in commercial taxes between the two areas.
◦
(–35,882.27, –26,011.70)
◦
(–35,588.26, –26,011.70)
◦
(–38,320.51, –23,279.50)
◦
(–35,746.04, –25,854.00)
The logistic growth model does not describe all populations.
Growth of Suburban St. Louis, 1950–1960
Small Town USA: Struggling to Survive
Growth in Cold and Cool Clouds
Growth Accounting for Europe, A.D. 500–1700
Find the voltage, current and power for each resistor in the circuit below