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Author Question: Exhibit 10-10SSTR = 6,750H0: 1=2=3=4SSE = 8,000Ha: at least one mean is differentnT = 20Refer to ... (Read 27 times)

madimontg

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Question 1

Exhibit 10-10

SSTR = 6,750H0: μ1=μ2=μ3=μ4
SSE = 8,000Ha: at least one mean is different
nT = 20 

Refer to Exhibit 10-10. The test statistic to test the null hypothesis equals


0.22


0.84


4.22


4.5



Question 2

Exhibit 10-10

SSTR = 6,750H0: μ1=μ2=μ3=μ4
SSE = 8,000Ha: at least one mean is different
nT = 20 

Refer to Exhibit 10-10. The null hypothesis is to be tested at the 5% level of significance. The p-value is


less than .01


between .01 and .025


between .025 and .05


between .05 and .10



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Marked as best answer by madimontg on Mar 25, 2023

labrinker

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madimontg

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Reply 2 on: Mar 25, 2023
Wow, this really help


parker125

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

 

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