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Author Question: Exhibit 12-1The following information regarding a dependent variable (Y) and an independent variable ... (Read 9 times)

kmoyer2

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on: Mar 25, 2023

Question 1

Exhibit 12-10
The following information regarding a dependent variable Y and an independent variable X is provided.
 

n = 4

ΣX = 16

ΣY = 28

Σ (Y -)(X - ) = -8

Σ (X - )2= 8

SST = 42

SSE = 34

 


Refer to Exhibit 12-10. The point estimate of Y when X = -3 is


◦

11


◦

14


◦

8


◦

0



Question 2

Exhibit 12-1
The following information regarding a dependent variable (Y) and an independent variable (X) is provided.

Y

X

4

2

3

1

4

4

6

3

8

5


SSE = 6
SST = 16


Refer to Exhibit 12-1. The least squares estimate of the Y intercept is


◦

1


◦

2


◦

3


◦

4

Essentials of Statistics for Business and Economics ¦ Anderson, Sweeney, Williams, Camm, Cochran ¦ 7th Edition
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Marked as best answer by kmoyer2 on Mar 25, 2023

butterfly17

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Reply #1 on: Mar 25, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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kmoyer2

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Reply 2 on: Mar 25, 2023
:D TYSM

vickybb89

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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