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Author Question: A random sample of 49 lunch customers was taken at a restaurant. The average amount of time the ... (Read 17 times)

sreghbsidhgjbndskijgnio

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on: Mar 25, 2023

A random sample of 49 lunch customers was taken at a restaurant. The average amount of time the customers in the sample stayed in the restaurant was 45 minutes with a standard deviation of 14 minutes.

a.Compute the standard error of the mean.
b.With a .95 probability, what statement can be made about the size of the margin of error?
c.Construct a 95% confidence interval for the true average amount of time customers spent in the restaurant.
d.With a .95 probability, how large of a sample would have to be taken to provide a margin of error of 2.5 minutes or less?

Essentials of Statistics for Business and Economics ¦ Anderson, Sweeney, Williams, Camm, Cochran ¦ 7th Edition
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Marked as best answer by sreghbsidhgjbndskijgnio on Mar 25, 2023

kaelamcrone

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Reply #1 on: Mar 25, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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sreghbsidhgjbndskijgnio

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Reply 2 on: Mar 25, 2023
Gracias!

xthemafja

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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