Author Question: The reaction of 44.1 g of Cr2O3 with 35.0 g of Al produced 25.6 g of Cr. What is the percent yield ... (Read 42 times)

jacob816 · **on:** Nov 5, 2023

Question 1

The percent composition by mass of an unknown chlorinated hydrocarbon was found to be 37.83% C, 6.35% H, and 55.83% Cl by mass. What is the empirical formula of this compound?
◦ C₂H₄Cl
◦ C₃H₇Cl
◦ C₃H₆Cl₂

◦ C₄H₉Cl
◦ C₅H₁₁Cl

Question 2

The reaction of 44.1 g of Cr₂O₃ with 35.0 g of Al produced 25.6 g of Cr. What is the percent yield for this reaction?
2Al + Cr₂O₃→ Al₂O₃ + 2Cr
◦ 37.9 %
◦ 58.0 %
◦ 73.1 %
◦ 84.9%
◦ 100. %

kalimarie · **Reply #1 on:** Nov 5, 2023

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