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Author Question: The reaction of 44.1 g of Cr2O3 with 35.0 g of Al produced 25.6 g of Cr. What is the percent yield ... (Read 66 times)

jacob816

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Question 1

The percent composition by mass of an unknown chlorinated hydrocarbon was found to be 37.83% C, 6.35% H, and 55.83% Cl by mass. What is the empirical formula of this compound?
◦ C2H4Cl
◦ C3H7Cl
◦ C3H6Cl2

◦ C4H9Cl
◦ C5H11Cl

Question 2

The reaction of 44.1 g of Cr2O3 with 35.0 g of Al produced 25.6 g of Cr. What is the percent yield for this reaction?
         2Al + Cr2O3→ Al2O3 + 2Cr
◦ 37.9 %
◦ 58.0 %
◦ 73.1 %
◦ 84.9%
◦ 100. %


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Marked as best answer by jacob816 on Nov 5, 2023

kalimarie

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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jacob816

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Reply 2 on: Nov 5, 2023
:D TYSM


irishcancer18

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

 

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