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Author Question: What is the theoretical yield of ammonia that can be obtained from the reaction of 10.0 g of H2 and ... (Read 53 times)

Ale

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on: Nov 5, 2023

Question 1

What is the molecular mass of nicotine, C10H14N2?
◦ 27.03 amu
◦ 148.22 amu
◦ 149.13 amu
◦ 81.12 amu
◦ 162.23 amu

Question 2

What is the theoretical yield of ammonia that can be obtained from the reaction of 10.0 g of H2 and excess N2?
         N2 + 3H2→ 2NH3

◦ 28.4 g
◦ 48.6 g
◦ 56.3 g
◦ 90.0 g
◦ 97.1 g
Chemistry ¦ Chang, Goldsby ¦ 11th Edition
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Marked as best answer by Ale on Nov 5, 2023

jacquelyngibson

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Reply #1 on: Nov 5, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Ale

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Reply 2 on: Nov 5, 2023
Gracias!

kusterl

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Reply 3 on: Yesterday
Wow, this really help

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