Author Question: When 20.0 mL of a 0.250 M (NH4)2S solution is added to 150.0 mL of a solution of Cu(NO3)2, a CuS ... (Read 52 times)

mmmmm · **on:** Nov 5, 2023

Question 1

What volume (mL) of a 0.3428 M HCl(aq) solution is required to completely neutralize 23.55 mL of a 0.2350 M Ba(OH)₂(aq) solution?
◦ 55.34 mL
◦ 11.07 mL
◦ 16.14 mL
◦ 32.29 mL
◦ 47.10 mL

Question 2

When 20.0 mL of a 0.250 M (NH₄)₂S solution is added to 150.0 mL of a solution of Cu(NO₃)₂, a CuS precipitate forms. The precipitate is then filtered from the solution, dried, and weighed. If the recovered CuS is found to have a mass of 0.3491 g, what was the concentration of copper ions in the original Cu(NO₃)₂ solution?
◦ 3.65 × 10^–3 M
◦ 1.22 × 10^–2 M
◦ 3.33 × 10^–2 M
◦ 4.87 × 10^–2 M
◦ 2.43 × 10^–2 M

Jim457 · **Reply #1 on:** Nov 5, 2023

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