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Author Question: When 38.0 mL of 0.1250 M H2SO4 is added to 100. mL of a solution of PbI2, a precipitate of PbSO4 ... (Read 57 times)

joe3899

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on: Nov 5, 2023
When 38.0 mL of 0.1250 M H2SO4 is added to 100. mL of a solution of PbI2, a precipitate of PbSO4 forms.  The PbSO4 is then filtered from the solution, dried, and weighed.  If the recovered PbSO4 is found to have a mass of 0.0471 g, what was the concentration of iodide ions in the original solution?
◦ 3.10 × 10–4 M
◦ 1.55 × 10–4 M
◦ 6.20 × 10–3 M
◦ 3.11 × 10–3 M
◦ 1.55 × 10–3 M
Chemistry ¦ Chang, Goldsby ¦ 11th Edition
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Marked as best answer by joe3899 on Nov 5, 2023

rika06@comcast.net

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Reply #1 on: Nov 5, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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joe3899

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Reply 2 on: Nov 5, 2023
Thanks for the timely response, appreciate it

ecabral0

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Reply 3 on: Yesterday
Gracias!

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