Calculate the standard enthalpy of formation of liquid methanol, ...

[booty5]

Question 1

Calculate the standard enthalpy change for the reaction
4A + 2B → 2AB + A₂
Given:

2A + B → A2B	ΔH° = – 25.0 kJ/mol
2A2B → 2AB + A2	ΔH° = 35.0 kJ/mol

 

◦ – 95.0 kJ/mol
◦ – 60.0 kJ/mol
◦ – 15.0 kJ/mol
◦ 10.0 kJ/mol
◦ 45.0 kJ/mol

Question 2

Calculate the standard enthalpy of formation of liquid methanol, CH₃OH(l), using the following information:

C(graph) + O2→ CO2(g)	ΔH° = –393.5 kJ/mol
H2(g) + (1/2)O2→ H2O(l)	ΔH° = –285.8 kJ/mol
CH3OH(l) + (3/2)O2(g) → CO2(g) + 2H2O(l)	ΔH° = –726.4 kJ/mol

 

◦ –1,691.5 kJ/mol
◦ –238.7 kJ/mol
◦ –47.1 kJ/mol
◦ 47.1 kJ/mol
◦ 1691.5 kJ/mol

[ekattan2]

A FREE account is required to view all solutions! Click to Register

Login with Facebook Login with Google Login with Email

Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.

Answer Preview

Only 35% of students answer this correctly

[booty5]

YES! Correct, THANKS for helping me on my review

[lindahyatt42]

Great answer, keep it coming