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Author Question: Octane (C8H18) undergoes combustion according to the following thermochemical equation: 2C8H18(l) ... (Read 49 times)

dhsndn

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on: Nov 5, 2023
Octane (C8H18) undergoes combustion according to the following thermochemical equation:
         2C8H18(l) + 25O2(g) → 16CO2(g) + 18H2O(l)       ΔH°rxn = –11,020 kJ/mol.
Given that ΔH°f[CO2(g)] = –393.5 kJ/mol and ΔH°f[H2O(l)] = –285.8 kJ/mol, calculate the standard enthalpy of formation of octane.
◦ –210 kJ/mol
◦ –11,230 kJ/mol
◦ 22,040 kJ/mol
◦ –420 kJ/mol
◦ 420 kJ/mol
Chemistry ¦ Chang, Goldsby ¦ 11th Edition
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Marked as best answer by dhsndn on Nov 5, 2023

KeriJennin

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Reply #1 on: Nov 5, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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dhsndn

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Reply 2 on: Nov 5, 2023
Thanks for the timely response, appreciate it

coreycathey

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Reply 3 on: Yesterday
:D TYSM

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