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Author Question: BeF42 is called the fluoberyllate ion. The formal charge on the beryllium atom in this ion is (Read 10 times)

bryantpr01

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on: Nov 5, 2023

Question 1

Assuming the octet rule is obeyed, how many covalent bonds will an oxygen atom form to give a formal charge of zero?
◦ 0
◦ 1
◦ 2
◦ 3
◦ 4

Question 2

BeF42– is called the fluoberyllate ion.  The formal charge on the beryllium atom in this ion is
◦ –2
◦ –1
◦ 0
◦ +1
◦ +2
Chemistry ¦ Chang, Goldsby ¦ 11th Edition
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Marked as best answer by bryantpr01 on Nov 5, 2023

ElaneShive

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Reply #1 on: Nov 5, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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bryantpr01

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Reply 2 on: Nov 5, 2023
YES! Correct, THANKS for helping me on my review

coreycathey

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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