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Author Question: Consider the weak bases below and their Kb values:C6H7OKb = 1.3 1010C2H5NH2Kb = 5.6 104C5H5NKb = ... (Read 64 times)

caca31

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on: Nov 5, 2023
Consider the weak bases below and their Kb values:
C6H7O
Kb = 1.3 × 10–10
C2H5NH2
Kb = 5.6 × 10–4
C5H5N
Kb = 1.7 × 10–9
Arrange the conjugate acids of these weak bases in order of increasing acid strength.

◦ C5H5NH+< C6H7OH < C2H5NH
◦ C6H7OH < C5H5NH+ < C2H5NH
◦ C5H5NH+< C2H5NH3+ < C6H7OH
◦ C6H7OH < C2H5NH3+< C5H5NH+

◦ C2H5NH3+< C5H5NH+ < C6H7OH
Chemistry ¦ Chang, Goldsby ¦ 11th Edition
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Marked as best answer by caca31 on Nov 5, 2023

wangyichun

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Reply #1 on: Nov 5, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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caca31

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Reply 2 on: Nov 5, 2023
Excellent

pangili4

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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