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Author Question: In the reaction: CH3COOH(aq) + NH2 (aq) CH3COO (aq) + NH3(aq), the conjugate acid-base pairs are: (Read 58 times)

warrenjean01

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on: Nov 5, 2023
In the reaction: CH3COOH(aq) + NH2– (aq) CH3COO– (aq)  +  NH3(aq), the conjugate acid-base pairs are:
◦ pair 1: CH3COOH and CH3COO– ; pair 2: NH2– and NH3

◦ pair 1: CH3COOH and NH3; pair 2: NH2– and CH3COO–

◦ pair 1: CH3COOH and NH2– ; pair 2: NH3 and CH3OO–

◦ pair 1: CH3COOH and CH3COO– ; pair 2: NH4+ and NH3

◦ pair 1: CH3COOH and CH3COO– ; pair 2: NH2– and NH3+
Chemistry ¦ Chang, Goldsby ¦ 11th Edition
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Marked as best answer by warrenjean01 on Nov 5, 2023

Deonnak85

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Reply #1 on: Nov 5, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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warrenjean01

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Reply 2 on: Nov 5, 2023
Great answer, keep it coming :)

cassie_ragen

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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