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Author Question: Find the concentration of Pb2+ ions in a solution made by adding 5.00 g of lead(II) iodide to 500. ... (Read 47 times)

bvyeehaw

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on: Nov 5, 2023

Question 1

Find the concentration of calcium ions in a solution made by adding 3.50 g of calcium fluoride to 750. mL of 0.125 M NaF.  [For CaF2, Ksp = 3.95 × 10–11.]
◦ 3.16 × 10–10 M
◦ 2.53 × 10–9 M
◦ 4.29 × 10–4 M
◦ 6.32 × 10–10 M
◦ 2.15 × 10–4 M

Question 2

Find the concentration of Pb2+ ions in a solution made by adding 5.00 g of lead(II) iodide to 500. mL of 0.150 M KI.  [For PbI2, Ksp = 1.39 × 10–8.]
◦ 3.04 × 10–4 M
◦ 1.54 × 10–7 M
◦ 6.18 × 10–7 M
◦ 1.52 × 10–4 M
◦ 9.27 × 10–8 M
Chemistry ¦ Chang, Goldsby ¦ 11th Edition
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Marked as best answer by bvyeehaw on Nov 5, 2023

dianagarcia

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Reply #1 on: Nov 5, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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bvyeehaw

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Reply 2 on: Nov 5, 2023
Wow, this really help

dantucker

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Reply 3 on: Yesterday
Gracias!

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