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Author Question: For the reaction SbCl5(g) SbCl3(g) + Cl2(g), Gf (SbCl5) = 334.34 kJ/mol Gf (SbCl3) = 301.25 ... (Read 34 times)

olgamartinez04

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on: Nov 5, 2023

Question 1

For the reaction SbCl5(g) SbCl3(g) + Cl2(g),
         ΔG°f (SbCl5) = –334.34 kJ/mol
         ΔG°f (SbCl3) = –301.25 kJ/mol
         ΔH°f (SbCl5) = –394.34 kJ/mol
         ΔH°f (SbCl3) = –313.80 kJ/mol
Will this reaction proceed spontaneously at 298 K and 1 atm pressure?


Question 2

For the reaction SbCl5(g) SbCl3(g) + Cl2(g),
         ΔG°f (SbCl5) = –334.34 kJ/mol
         ΔG°f (SbCl3) = –301.25 kJ/mol
         ΔH°f (SbCl5) = –394.34 kJ/mol
         ΔH°f (SbCl3) = –313.80 kJ/mol
Calculate ΔG at 800 K and 1 atm pressure (assume ΔS°and ΔH° do not change with temperature).
Chemistry ¦ Chang, Goldsby ¦ 11th Edition
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Marked as best answer by olgamartinez04 on Nov 5, 2023

Sophia0717

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Reply #1 on: Nov 5, 2023
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olgamartinez04

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Reply 2 on: Nov 5, 2023
YES! Correct, THANKS for helping me on my review

scikid

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Reply 3 on: Yesterday
Wow, this really help

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