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Author Question: Consider an electrochemical cell involving the overall reaction 2AgBr(s) + Pb(s) Pb2+ + 2Ag(s) + ... (Read 3 times)

lingual

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on: Nov 5, 2023
Consider an electrochemical cell involving the overall reaction
         2AgBr(s) + Pb(s) → Pb2+ + 2Ag(s) + 2Br–
Each half-reaction is carried out in a separate compartment.  The anion included in the lead half-cell is NO3–.  The cation in the silver half-cell is K+.  The two half-cells are connected by a KNO3 salt bridge.  If [Pb2+] = 1.0 M, what concentration of Br– ion will produce a cell emf of 0.25 V at 298 K?
         Given:  AgBr(s) + e–→ Ag + Br–, E° = +0.07 V.
◦ 0.02 M
◦ 0.14 M
◦ 0.38 M
◦ 1.0 M
◦ 7.0 M
Chemistry ¦ Chang, Goldsby ¦ 11th Edition
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Marked as best answer by lingual on Nov 5, 2023

nora9826

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Reply #1 on: Nov 5, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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lingual

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Reply 2 on: Nov 5, 2023
Great answer, keep it coming :)

Bigfoot1984

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Reply 3 on: Yesterday
Excellent

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