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Author Question: A lamp connected in series with a capacitor and an AC voltage source will light up. This is because: (Read 26 times)

desireelg_7

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on: Nov 27, 2023

Question 1

A capacitor is charged by connecting it in series with a resistor to a DC source. The greatest change in voltage across the capacitor will occur during:  


◦

the first time-constant period.


◦

the second time-constant period.


◦

the fourth time-constant period.


◦

the fifth time-constant period.



Question 2

A lamp connected in series with a capacitor and an AC voltage source will light up. This is because:  


◦

the dielectric is shorted out automatically when alternating current is applied.


◦

the peak AC voltage, being higher than the equivalent DC voltage, can temporarily break down the dielectric.


◦

the lamp is also acting as a capacitor when connected in series with an actual capacitor.


◦

the capacitor is being alternately charged and discharged, resulting in a continuous flow of current through the lamp.

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Marked as best answer by desireelg_7 on Nov 27, 2023

avelasquez

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Reply #1 on: Nov 27, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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desireelg_7

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Reply 2 on: Nov 27, 2023
Great answer, keep it coming :)

kalskdjl1212

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Reply 3 on: Yesterday
Wow, this really help

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