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Author Question: For the circuit shown (no capacitor), the current flow through the inductor would be (Read 44 times)

M1ch3a

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on: Nov 27, 2023

Question 1

Any time the power factor drops to less than ________ the circuit or system is considered to have a poor power factor.


◦

0.25


◦

0.60


◦

0.85


◦

0.95



Question 2

For the circuit shown (no capacitor), the current flow through the inductor would be


◦

11 A.


◦

12 A.


◦

13 A.


◦

14 A.

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Marked as best answer by M1ch3a on Nov 27, 2023

Htimsrs

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Reply #1 on: Nov 27, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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M1ch3a

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Reply 2 on: Nov 27, 2023
Great answer, keep it coming :)

apple

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Reply 3 on: Yesterday
:D TYSM

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