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Author Question: For the circuit shown (no capacitor), the reactive power would be (Read 48 times)

fungirl

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on: Nov 27, 2023

Question 1

For the circuit shown (no capacitor), the power factor would be


◦

50 percent lagging.


◦

50 percent leading.


◦

60 percent lagging.


◦

60 percent leading.



Question 2

For the circuit shown (no capacitor), the reactive power would be


◦

1356 VARs.


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1498 VARs.


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1559 VARs.


◦

1600 VARs.

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Marked as best answer by fungirl on Nov 27, 2023

miro2222

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Reply #1 on: Nov 27, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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fungirl

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Reply 2 on: Nov 27, 2023
:D TYSM

triiciiaa

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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