Author Question: A researcher wishes to test H0: 1 = 2 = 3 against H1:at least one of the means is different. Based ... (Read 64 times)

jrubin · **on:** Jan 16, 2020

A researcher wishes to test H₀: μ₁ = μ₂ = μ₃ against H₁:at least one of the means is different. Based on the ANOVA table below, if the level of significance is α = 0.01, is it necessary to conduct Tukey's test? If the level of significance is α = 0.05, is it necessary to conduct Tukey's test? Explain.

SOURCE

df

SS

MS

F p

______________________________________________________________

Treatments

2

86.22

43.11

13.15 0.0174

Blocks

2 0.889 0.444 0.136 0.8767

Error

4

13.11

3

.28

______________________________________________________________
Total 8 100.22

◦ no, H₀ not rejected; yes, H₀ rejected, at least one mean found to be different
◦ yes, H₀ rejected, at least one mean found to be different; yes, H₀ rejected, at least one mean found to be different
◦ yes, H₀ rejected, at least one mean found to be different ; no, H₀ not rejected
◦ no, H₀ not rejected; no, H₀ not rejected;

Loise Hard · **Reply #1 on:** Jan 16, 2020

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