Author Question: A 1.75-g sample of a metal chloride, MCl2, is dissolved in water and treated with excess aqueous ... (Read 59 times)

sarasara · **on:** Mar 21, 2021

Question 1

A 0.307-g sample of an unknown triprotic acid is titrated to the third equivalence point using 35.2 mL of 0.106 M NaOH. Calculate the molar mass of the acid.

◦ 247 g/mol
◦ 171 g/mol
◦ 165 g/mol
◦ 151 g/mol
◦ 82.7 g/mol

Question 2

A 1.75-g sample of a metal chloride, MCl₂, is dissolved in water and treated with excess aqueous silver nitrate. The silver chloride that formed weighed 3.73 g. Calculate the molar mass of M.

◦ 70.9 g/mol
◦ 32 g/mol
◦ 63.5 g/mol
◦ 67 g/mol
◦ 72.4 g/mol

Animal_Goddess · **Reply #1 on:** Mar 21, 2021

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