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Author Question: A 1.75-g sample of a metal chloride, MCl2, is dissolved in water and treated with excess aqueous ... (Read 62 times)

sarasara

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on: Mar 21, 2021

Question 1

A 0.307-g sample of an unknown triprotic acid is titrated to the third equivalence point using 35.2 mL of 0.106 M NaOH. Calculate the molar mass of the acid.

◦ 247 g/mol
◦ 171 g/mol
◦ 165 g/mol
◦ 151 g/mol
◦ 82.7 g/mol

Question 2

A 1.75-g sample of a metal chloride, MCl2, is dissolved in water and treated with excess aqueous silver nitrate. The silver chloride that formed weighed 3.73 g. Calculate the molar mass of M.

◦ 70.9 g/mol
◦ 32 g/mol
◦ 63.5 g/mol
◦ 67 g/mol
◦ 72.4 g/mol
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Marked as best answer by sarasara on Mar 21, 2021

Animal_Goddess

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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sarasara

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Reply 2 on: Mar 21, 2021
Gracias!

CAPTAINAMERICA

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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