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Author Question: At a particular temperature, N2O5 decomposes according to a first-order rate law with a half-life of ... (Read 207 times)

bclement10

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on: Mar 21, 2021

Question 1

At a given temperature, a first-order reaction has a rate constant of 1.5 × 10–3 s–1. The time required for the reaction to be 32% completed is

◦ 13 min
◦ 1.9 min
◦ 47 min
◦ 4.3 min
◦ 39 min

Question 2

At a particular temperature, N2O5 decomposes according to a first-order rate law with a half-life of 3.0 s. If the initial concentration of N2O5 is 1.0 × 1016 molecules/cm3, what will be the concentration in molecules/cm3 after 15.5 s?

◦ 2.8 × 1014

◦ 3.3 × 101

◦ 1.0 × 1016

◦ 1.5 × 1014

◦ 2.3 × 10–1
Chemistry: An Atoms First Approach ¦ Zumdahl, DeCoste ¦ 3rd Edition
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Marked as best answer by bclement10 on Mar 21, 2021

Brummell1998

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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bclement10

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Reply 2 on: Mar 21, 2021
Excellent

jordangronback

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Reply 3 on: Yesterday
Gracias!

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