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Author Question: For the reaction: 2 N2O5(g) 4 NO2(g) + O2(g) the rate law is: = k[N2O5] At 300 K, the half-life is ... (Read 129 times)

aabwk4

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For the reaction: 2 N2O5(g) → 4 NO2(g) + O2(g) the rate law is:

= k[N2O5]

At 300 K, the half-life is 2.50 × 104 seconds and the activation energy is 103.3 kJ/mol O2. At the time when N2O5 is being consumed at a rate of 1.2 × 10-4 M/s, what is the rate at which NO2 is being formed?
◦ 1.2 × 10-4 M/s
◦ 2.4 × 10-4 M/s
◦ 6.0 × 10-5 M/s
◦ 3.0 × 10-5 M/s
◦ 4.8 × 10-4 M/s


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Marked as best answer by aabwk4 on Jul 8, 2021

perkiness

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aabwk4

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Reply 2 on: Jul 8, 2021
Great answer, keep it coming :)


kalskdjl1212

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Reply 3 on: Yesterday
Gracias!

 

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