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Author Question: Given the following information, calculate H (in kcal mol-1) for: LiCl(s) Cl-(g) + Li+(g) Process H ... (Read 34 times)

Chelseaamend

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on: Jul 8, 2021
Given the following information, calculate ΔH° (in kcal mol-1) for:  LiCl(s) → Cl-(g) + Li+(g)

Process  ΔH° (kcal mol-1)
Li(s) → Li(g)  +37
Li(g) → Li+(g) + e-  +124
Cl2(g) → 2 Cl(g)  +29 (per mole Cl)
Cl(g) + e-→ Cl-(g)  -83
2 Li(s) + Cl2(g) → 2 LiCl(s)  -109 (per mole LiCl)

◦ +73 kcal mol-1
◦ +148 kcal mol-1
◦ +216 kcal mol-1
◦ -96 kcal mol-1
◦ -49 kcal mol-1
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by Chelseaamend on Jul 8, 2021

fauacakatahaias

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Chelseaamend

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Reply 2 on: Jul 8, 2021
Great answer, keep it coming :)

at

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Reply 3 on: Yesterday
Gracias!

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