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Author Question: Given the following information, calculate H (in kcal mol-1) for: I(g) + e- I-(g) Process H (kcal ... (Read 23 times)

nramada

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on: Jul 8, 2021
Given the following information, calculate ΔH° (in kcal mol-1) for:  I(g) + e-→ I-(g)

Process  ΔH° (kcal mol-1)
Na(s) → Na(g)  +26
I2(g) → 2 I(g)  +36 (per mole I2)
I2(s) → I2(g)  +15
Na(g) → Na+(g) + e-  +118
NaI(s) → Na+(g) + I- (g)  +798
2 Na(s) + I2(s) → 2NaI(s)  -699 (per mole NaI)

◦ -633 kcal mol-1
◦ -450 kcal mol-1
◦ -71 kcal mol-1
◦ -696 kcal mol-1
◦ +712 kcal mol-1
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by nramada on Jul 8, 2021

TDubDCFL

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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nramada

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Reply 2 on: Jul 8, 2021
Wow, this really help

samiel-sayed

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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