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Author Question: Given the following information, calculate H (in kcal mol-1) for: I(g) + e- I-(g) Process H ... (Read 20 times)

Brittanyd9008

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Given the following information, calculate Δ(in kcal mol-1) for:  I(g) + e-→ I-(g)

Process  Δ (kcal/mole)
Ca(s) → Ca(g)  +178
I2(g) → 2 I(g)    +36 (per mole I2)
I2(s) → I2(g)    +15
Ca(g) → Ca+(g) + e-  +590
Ca+(g) → Ca+2(g) + e-  +1145
CaI2(s) → Ca+2(g) +2 I- (g) +1288
Ca(s) + I2(s) → CaI2(s)  +534 (per mole CaI2)  

◦ -715 kcal mol-1
◦ -338 kcal mol-1
◦ -89 kcal mol-1
◦ -71 kcal mol-1
◦ -142 kcal mol-1


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Marked as best answer by Brittanyd9008 on Jul 8, 2021

zhanghao

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Brittanyd9008

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Reply 2 on: Jul 8, 2021
YES! Correct, THANKS for helping me on my review


bblaney

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Reply 3 on: Yesterday
Great answer, keep it coming :)

 

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