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Author Question: A researcher wishes to test H0: 1 = 2 = 3 against H1:at least one of the means is different. Based ... (Read 68 times)

jrubin

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A researcher wishes to test H0: μ1 = μ2 = μ3 against H1:at least one of the means is different. Based on the ANOVA table below, if the level of significance is α = 0.01, is it necessary to conduct Tukey's test? If the level of significance is α = 0.05, is it necessary to conduct Tukey's test? Explain.

SOURCEdfSSMSF                 p
______________________________________________________________
Treatments286.22 43.1113.15            0.0174
Blocks2                   0.889           0.444             0.136            0.8767            
Error413.113.28
______________________________________________________________
Total                     8                  100.22

◦ no, H0 not rejected; yes, H0 rejected, at least one mean found to be different
◦ yes, H0 rejected, at least one mean found to be different; yes, H0 rejected, at least one mean found to be different
◦ yes, H0 rejected, at least one mean found to be different ; no, H0 not rejected
◦ no, H0 not rejected; no, H0 not rejected;


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Marked as best answer by jrubin on Jan 16, 2020

Loise Hard

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jrubin

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Reply 2 on: Jan 16, 2020
Thanks for the timely response, appreciate it


kthug

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Reply 3 on: Yesterday
Excellent

 

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