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Author Question: An element Y, has the following ionization energies Ei1 = 578 kJ/mol Ei2 = 1,817 kJ/mol Ei3 = 2,745 ... (Read 104 times)

SAVANNAHHOOPER23

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on: Feb 15, 2020

Question 1

Which period 2 element has successive first through seventh ionization energies (kJ/mol) of
Ei1 = 1,402; Ei2 =2,856; Ei3 =4,578; Ei4 =7,475; Ei5 =9,445; Ei6 =53,267; and Ei7 = 64,360?
◦ B
◦ O
◦ C
◦ N

Question 2

An element Y, has the following ionization energies

Ei1 = 578 kJ/mol
Ei2 = 1,817 kJ/mol
Ei3 = 2,745 kJ/mol
Ei4 = 11,575 kJ/mol

What is the most likely identity for this element?
◦ Mg
◦ Si
◦ Na
◦ Al
Chemistry ¦ McMurry, Fay, Robinson ¦ 7th Edition
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Marked as best answer by SAVANNAHHOOPER23 on Feb 15, 2020

hramirez205

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Reply #1 on: Feb 15, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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SAVANNAHHOOPER23

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Reply 2 on: Feb 15, 2020
Thanks for the timely response, appreciate it

bimper21

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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