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Author Question: Analyze the following code.class Test { public static void main(String[] args) { String ... (Read 100 times)

Kikoku

  • Hero Member
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on: May 6, 2020
Analyze the following code.

class Test {
public static void main(String[] args) {
​String s;
​System.out.println("s is " + s);
}
}

◦ The program has a compilation error because s is not initialized, but it is referenced in the println statement.
◦ The program has a runtime error because s is not initialized, but it is referenced in the println statement.
◦ The program compiles and runs fine.
◦ The program has a runtime error because s is null in the println statement.
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Marked as best answer by Kikoku on May 6, 2020

Kdiggy

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Reply #1 on: May 6, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Kikoku

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  • Posts: 540
Reply 2 on: May 6, 2020
Gracias!

connor417

  • Member
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Reply 3 on: Yesterday
Great answer, keep it coming :)

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