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Author Question: Analyze the following code.class Test { public static void main(String[] args) { String ... (Read 98 times)

Kikoku

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  • Posts: 540
Analyze the following code.

class Test {
public static void main(String[] args) {
String s;
System.out.println("s is " + s);
}
}

◦ The program has a compilation error because s is not initialized, but it is referenced in the println statement.
◦ The program has a runtime error because s is not initialized, but it is referenced in the println statement.
◦ The program compiles and runs fine.
◦ The program has a runtime error because s is null in the println statement.


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Marked as best answer by Kikoku on May 6, 2020

Kdiggy

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Kikoku

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  • Posts: 540
Reply 2 on: May 6, 2020
YES! Correct, THANKS for helping me on my review


ghepp

  • Member
  • Posts: 361
Reply 3 on: Yesterday
Wow, this really help

 

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