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Author Question: When 50.0 mL of 0.400 mol L-1 Ca(NO3)2 is added to 50.0 mL of 0.800 mol L-1 NaF, CaF2 precipitates, ... (Read 130 times)

Kikoku

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When 50.0 mL of 0.400 mol L-1 Ca(NO3)2 is added to 50.0 mL of 0.800 mol L-1 NaF, CaF2 precipitates, as shown in the net ionic equation below. The initial temperature of both solutions is 23.0 °C. Assuming that the reaction goes to completion, and that the resulting solution has a mass of 100.00 g and a specific heat of 4.18 J g-1°C-1, calculate the final temperature of the solution.

Ca2+(aq) + 2 F-(aq) → CaF2(s) ΔrH = -11.5 kJ

◦ 22.45 °C
◦ 23.55 °C
◦ 24.10 °C
◦ 24.65 °C


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Marked as best answer by Kikoku on Jul 8, 2021

xthemafja

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Kikoku

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Reply 2 on: Jul 8, 2021
Great answer, keep it coming :)


abro1885

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

 

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