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Author Question: The rate law for the reaction 2NO2 + O3 N2O5 + O2 is rate = k[NO2][O3]. Which one of the following ... (Read 11 times)

tspaw0811

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on: Nov 5, 2023
The rate law for the reaction 2NO2 + O3→ N2O5 + O2 is rate = k[NO2][O3].  Which one of the following mechanisms is consistent with this rate law?
◦ NO2 + NO2→ N2O4                (fast)
N2O4 + O3→ N2O5 + O2     (slow)
◦ NO2 + O3→ NO5                           (fast)
NO5 + NO5→ N2O5 + 5/2O2     (slow)
◦ NO2 + O3→ NO3 + O2     (slow)
NO3 + NO2→ N2O5           (fast)
◦ NO2 + NO2→ N2O2 + O2     (slow)
N2O2 + O3→ N2O5                   (fast)
Chemistry ¦ Chang, Goldsby ¦ 11th Edition
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Marked as best answer by tspaw0811 on Nov 5, 2023

nikspatel037

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Reply #1 on: Nov 5, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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tspaw0811

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Reply 2 on: Nov 5, 2023
Excellent

bassamabas

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Reply 3 on: Yesterday
:D TYSM

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