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Author Question: An atom with one valence electron combines with an atom with seven valence electrons. What is likely to happen? (Read 975 times)

luvbio

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on: Sep 20, 2013
A.It will share its valence electron with the other atom.
B.It will take one electron from the other atom.
C.It will give up its valence electron to the other atom.
D.It will take all seven electrons from the other atom.


frankwu

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Reply #1 on: Sep 20, 2013
C.It will give up its valence electron to the other atom.


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mydiamond

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Reply #2 on: Sep 20, 2013
Sodium (a reactive alkali metal with one valence electron), forms a strong (ionic) bond with
Chlorine (a halogen with 7 valence electrons).
I'm guessing: Answer (A) (they share the electron to form the bond).

PS: For practical purposes, the electron in an ionic bond is lost.
       Static charge bonds the anion and cation.
       However, no bond is purely ionic; so the loss is incomplete while the resulting substance
       remains crystalline.
       Your answer could be (C) - consult your text.


mcmcdaniel

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Reply #3 on: Sep 20, 2013
The answer is C - It will give up its valence electron to the other atom.

For example, one valence electron sodium, Na, combines with seven valence electron Chlorine, Cl.

Both atoms want to have a complete 8 valence electron outer shell. Sodium wants to lose its one valence electron and chlorine wants to gain one. So the sodium gives up its electron to the chlorine to form sodium chloride, an ionic salt.


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