Referring to Table , determine what percentage of the average ...

[go.lag]

Referring to Table , determine what percentage of the average familys
  monthly irrigation needs could be met using the water harvested from the
  rooftop in this storm. (Hint: Divide the answer to question c by the
  number of gallons used for monthly irrigation Table  and multiply the
  result by .) What will be an ideal response?

Question 2

If the roof area of an average-sized home is  m, how much water could
  be collected from the roof of an average home in the same storm? What will be an ideal response?

[fdliggud]

Answer to Question 1

(990 gal  1440 gal) x 100 = 69

Answer to Question 2

a. Convert . cm of rainfall to meters.
2.5 cm  100 cm/m = 0.025 m
b. Multiply your answer to a by the roof area to get the volume of
water in m.
0.025 m x 150 m2 = 3.75 m3
c. Convert your answer to b to gallons.
3.75 m3 x 264 gal per m3 = 990 gal

[go.lag]

Thanks for the timely response, appreciate it

[amcvicar]

Gracias!