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Author Question: An npn BJT has the following values: VCC = +15 V, RC = 1.5 k, RB = 47 k, and hFE = 80 at IC = 10 mA. ... (Read 37 times)

londonang

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on: Jul 28, 2018
An npn BJT has the following values: VCC = +15 V, RC = 1.5 k, RB = 47 k, and hFE = 80 at IC = 10 mA. The minimum value of +Vin required to saturate the transistor is
 
  A) 1.25 V B) 15 V C) 6.58 V D) 5.88 V

Question 2

An NPN transistor will be open from emitter to collector when
 
  A) the base is more positive than the emitter. B) the base is more negative than the emitter.
  C) the emitter is more positive than the collector. D) the collector is more positive than the emitter.


EAN94

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Reply #1 on: Jul 28, 2018
Answer to Question 1

C

Answer to Question 2

B


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