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Author Question: The heat of vaporization of ethyl alcohol Lv is about 200 cal/g. That means that 1 gram of this ... (Read 90 times)

Anajune7

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The heat of vaporization of ethyl alcohol Lv is about 200 cal/g. That means that 1 gram of this refrigerant upon vaporization would release
 
  A) less then 200 calories.
  B) 200 calories.
  C) more than 200 calories.

Question 2

Which requires more energy?
 
  A) melting a gram of 0C ice
  B) increasing the temperature of 1 gram of water from 0C to 100C
  C) changing 1 gram of 100C water to 100C steam
  D) all the same



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AaaA

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Answer to Question 1

Answer: B

Answer to Question 2

Answer: C




AaaA

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