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Author Question: The quantitative amount of charge separation in a diatomic molecule contributes to the dipole moment ... (Read 89 times)

sc00by25

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on: Aug 27, 2018
The quantitative amount of charge separation in a diatomic molecule contributes to the dipole moment of that molecule.
 
  Indicate whether the statement is true or false

Question 2

Find E for the reaction below if the process is carried out at a constant pressure of 1.00 atm and V (the volume change) = -24.5 L. (1 L  atm = 101 J) 2 CO(g) + O2 (g)  2 CO2(g) H = -566. kJ
 
  A) +2.47 kJ
  B) -2.47 kJ
  C) -564 kJ
  D) -568 kJ

Question 3

Why are chlorofluorocarbons so damaging to the ozone layer when they are such stable molecules?
 
  A) They contain a double bond that ozone readily attacks, resulting in the destruction of the ozone.
  B) They are very light molecules that rapidly diffuse into the upper atmosphere and block the radiation that causes formation of ozone.
  C) They are greenhouse gases that raise the temperature above the dissociation temperature of ozone.
  D) The radiation in the stratosphere dissociates them producing chlorine atoms that catalytically destroy ozone.
  E) CFCs do not damage the ozone.
Chemistry: The Central Science ¦ Brown, LeMay, Bursten ¦ 14th Edition
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macmac

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Reply #1 on: Aug 27, 2018
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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sc00by25

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Reply 2 on: Aug 27, 2018
Great answer, keep it coming :)

yeungji

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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