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Author Question: 8.000 moles of H2(g) reacts with 4.000 mol of O2(g) to form 8.000 mol of H2O(l) at 25 C and a ... (Read 168 times)

DyllonKazuo

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on: Nov 18, 2019

Question 1

For a particular process that is carried out at constant pressure, q = 145 kJ and w = -35 kJ. Therefore,
◦ ΔU = 180 kJ and ΔH = 145 kJ.
◦ ΔU = 110 kJ and ΔH = 145 kJ.
◦ ΔU = 145 kJ and ΔH = 110 kJ.
◦ ΔU = 145 kJ and ΔH = 180 kJ.

Question 2

8.000 moles of H2(g) reacts with 4.000 mol of O2(g) to form 8.000 mol of H2O(l) at 25 °C and a constant pressure of 1.0133 bar. If 546.4 kJ of heat are released during this reaction, and PΔV is equal to -29.60 kJ, then
◦ ΔH° = -546.4 kJ and ΔU° = -516.8 kJ.
◦ ΔH° = +546.4 kJ and ΔU° = +576.06 kJ.
◦ ΔH° = -546.4 kJ and ΔU° = -576.0 kJ.
◦ ΔH° = +546.4 kJ and ΔU° = +516.8 kJ.
Chemistry: A Molecular Approach (Canadian) ¦ Tro, Fridgen, Shaw ¦ 2nd Edition
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Marked as best answer by DyllonKazuo on Nov 18, 2019

batool

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Reply #1 on: Nov 18, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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DyllonKazuo

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Reply 2 on: Nov 18, 2019
Great answer, keep it coming :)

yeungji

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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