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Author Question: Choose the solvent below that would show the greatest boiling point elevation when used to make a ... (Read 66 times)

pragya sharda

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Question 1

Calculate the freezing point of a solution of 500.0 g of ethylene glycol (C2H6O2) dissolved in 500.0 g of water. Kf = 1.86 °C m-1 and Kb = 0.512 °C m-1.
◦ -30.0 °C
◦ 8.32 °C
◦ 30.0 °C
◦ 70.2 °C
◦ -8.32 °C

Question 2

Choose the solvent below that would show the greatest boiling point elevation when used to make a 0.10 mol kg-1 nonelectrolyte solution.
◦ CHCl3, Kb = 4.70 °C m-1
◦ CH3CH2OH, Kb = 1.99 °C m-1
◦ CH3CH2OCH2CH3, Kb = 1.79 °C m-1
◦ C6H6, Kb = 5.12 °C m-1
◦ CCl4, Kb = 29.9 °C m-1


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Marked as best answer by pragya sharda on Nov 18, 2019

BUTTHOL369

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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pragya sharda

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Reply 2 on: Nov 18, 2019
Thanks for the timely response, appreciate it


Joy Chen

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Reply 3 on: Yesterday
Wow, this really help

 

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