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Author Question: A 25.0 mL sample of 0.150 mol L-1 acetic acid is titrated with a 0.150 mol L-1 NaOH solution. What ... (Read 139 times)

khang

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on: Nov 18, 2019

Question 1

A 25.0 mL sample of 0.150 mol L-1 hydrofluoric acid is titrated with a 0.150 mol L-1 NaOH solution. What is the pH before any base is added? Hydrofluoric acid is monoprotic. The Ka of hydrofluoric acid is 3.5 × 10-4.
◦ 2.15
◦ 7.07 × 10-3
◦ 2.33 × 10-3
◦ 2.63
◦ 3.46

Question 2

A 25.0 mL sample of 0.150 mol L-1 acetic acid is titrated with a 0.150 mol L-1 NaOH solution. What is the pH after 26.0 mL of base is added? The Ka of acetic acid is 1.8 × 10-5.
◦ 7.00
◦ 11.47
◦ 4.74
◦ 2.54
◦ 10.18
Chemistry: A Molecular Approach (Canadian) ¦ Tro, Fridgen, Shaw ¦ 2nd Edition
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Marked as best answer by khang on Nov 18, 2019

brittanywood

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Reply #1 on: Nov 18, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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khang

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Reply 2 on: Nov 18, 2019
Thanks for the timely response, appreciate it

rleezy04

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Reply 3 on: Yesterday
:D TYSM

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