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Author Question: What is the pH at the equivalence point of a weak base-strong acid titration if 20.00 mL of NaOCl ... (Read 32 times)

jman1234

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on: Nov 18, 2019

Question 1

What is the pH of a solution made by mixing 30.00 mL of 0.10 mol L-1 acetic acid (CH3COOH) with 50.00 mL of 0.100 mol L-1 KOH? Assume that the volumes of the solutions are additive. Ka = 1.8 × 10-5 for
◦ 12.40
◦ 11.13
◦ 9.26
◦ 8.26

Question 2

What is the pH at the equivalence point of a weak base-strong acid titration if 20.00 mL of NaOCl requires 28.30 mL of 0.50 mol L-1 HCl for complete neutralization? Ka = 3.0 × 10-8 for HOCl.
◦ 4.03
◦ 3.76
◦ 3.18
◦ 0.30
Chemistry: A Molecular Approach (Canadian) ¦ Tro, Fridgen, Shaw ¦ 2nd Edition
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Marked as best answer by jman1234 on Nov 18, 2019

gabrielle_lawrence

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Reply #1 on: Nov 18, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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jman1234

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Reply 2 on: Nov 18, 2019
:D TYSM

bdobbins

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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