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Author Question: Consider the following standard reduction potentials:Ni2+(aq) + 2 e- Ni(s)E = -0.26 VI2(s) + 2 e- ... (Read 117 times)

chads108

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on: Nov 18, 2019
Consider the following standard reduction potentials:

Ni2+(aq) + 2 e- → Ni(s)E° = -0.26 V
I2(s) + 2 e- → 2 I-(aq)E° = +0.54 V

Under standard conditions,
◦ I-(aq) is a stronger oxidizing agent than Ni(s), and I2(s) is a stronger reducing agent than Ni2+(aq).
◦ Ni2+(aq) is a stronger oxidizing agent than I2(s), and I-(aq) is a stronger reducing agent than Ni(s).
◦ Ni(s) is a stronger oxidizing agent than I-(aq), and Ni2+(aq) is a stronger reducing agent than I2(s).
◦ I2(s) is a stronger oxidizing agent than Ni2+(aq), and Ni(s) is a stronger reducing agent than I-(aq).
Chemistry: A Molecular Approach (Canadian) ¦ Tro, Fridgen, Shaw ¦ 2nd Edition
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Marked as best answer by chads108 on Nov 18, 2019

joechoochoy

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Reply #1 on: Nov 18, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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chads108

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Reply 2 on: Nov 18, 2019
Excellent

abro1885

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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