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Author Question: On an ordinary graph, unit times decrease at a decreasing rate, but on a log-log graph, the learning ... (Read 34 times)

tth

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on: Dec 3, 2019

Question 1

A firm that successfully pursues a steeper-than-industry-average learning curve and manages costs down may still fail if, by underestimating a strong competitor, it fails to gain the added volume necessary for the learning curve to exist.
◦ true
◦ false

Question 2

On an ordinary graph, unit times decrease at a decreasing rate, but on a log-log graph, the learning "curve" appears as a straight line.
◦ true
◦ false
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Marked as best answer by tth on Dec 3, 2019

raili21

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Reply #1 on: Dec 3, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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tth

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Reply 2 on: Dec 3, 2019
Gracias!

Joy Chen

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Reply 3 on: Yesterday
:D TYSM

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