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Author Question: Solve the problem.Among a random sample of 150 employees of a particular company, the mean commute ... (Read 144 times)

D2AR0N

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on: Jan 18, 2020

Question 1

Solve the problem.

Among a random  sample of 500  college students, the mean number of hours worked per week at non-college related jobs is 15.1. This mean lies 2.8 standard deviation(s) below the mean of the sampling distribution. If a second sample of 500 students is selected, what is the probability that for the second sample, the mean number of hours worked will be at least 15.1?
◦ 0.9974
◦ 0.9965
◦ 0.5
◦ 0.0026

Question 2

Solve the problem.

Among a random  sample of 150  employees of a particular company, the mean commute distance is
This mean lies 2.2 standard deviation(s) below the mean of the sampling distribution. If a second sample of 150 employees  is selected, what is the probability that for the second sample, the mean commute distance will be less than 29.5 miles?
◦ 0.9861
◦ 0.5
◦ 0.0139
◦ 0.0107
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Marked as best answer by D2AR0N on Jan 18, 2020

jlaineee

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Reply #1 on: Jan 18, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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D2AR0N

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Reply 2 on: Jan 18, 2020
Thanks for the timely response, appreciate it

xiazhe

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Reply 3 on: Yesterday
Wow, this really help

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