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Author Question: In the reaction 2 H2O2(l) 2 H2O(l) + O2(g) oxygen is (Read 68 times)

casperchen82

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Question 1

Disproportionation is a reaction in which a substance is both oxidized and reduced in the reaction. Which is a disproportionation reaction?
◦ ClO3-(aq) + 3 Cu(s) + 6 H+(aq) → Cl-(aq) + 3 Cu2+(aq) + 3 H2O(l)
◦ ClO-(aq) + Pb(OH)4-(aq) → Cl-(aq) + PbO2(s) + H2O(l) + 2 OH-(aq)
◦ Cl2(g) + 2 OH-(aq) → Cl-(aq) + ClO-(aq) + H2O(l)
◦ 6 Cl-(aq) + Cr2O72-(aq) + 14 H+(aq) → 3 Cl2(g) + 2 Cr3+(aq) + 7 H2O(l)

Question 2

In the reaction 2 H2O2(l) → 2 H2O(l) + O2(g) oxygen is
◦ both oxidized and reduced.
◦ neither oxidized nor reduced.
◦ only reduced.
◦ only oxidized.


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Marked as best answer by casperchen82 on Feb 15, 2020

Amiracle

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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casperchen82

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Reply 2 on: Feb 15, 2020
Thanks for the timely response, appreciate it


sarah_brady415

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Reply 3 on: Yesterday
Wow, this really help

 

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