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Author Question: What is the pH of a 2.4 M pyridine solution that has Kb = 1.9 10-9? The equation for the ... (Read 101 times)

tuffie

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on: Feb 15, 2020

Question 1

What is the pH of a 0.300 M NH3 solution that has Kb = 1.8 × 10-5? The equation for the dissociation of NH3 is

NH3(aq) + H2O(l) ⇌ NH4+(aq) + OH-(aq).


◦ 2.11
◦ 11.89
◦ 2.63
◦ 11.37

Question 2

What is the pH of a 2.4 M pyridine solution that has Kb = 1.9 × 10-9? The equation for the dissociation of pyridine is

C5H5N(aq) + H2O(l) ⇌ C5H5NH+(aq) + OH-(aq).


◦ 8.72
◦ 9.83
◦ 10.83
◦ 4.17
Chemistry ¦ McMurry, Fay, Robinson ¦ 7th Edition
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Marked as best answer by tuffie on Feb 15, 2020

batool

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Reply #1 on: Feb 15, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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tuffie

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Reply 2 on: Feb 15, 2020
Excellent

raenoj

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Reply 3 on: Yesterday
Gracias!

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